I needed this once, but I could not figure out how to just create the vars
in current scope.
If my_extract() is called from within a function, then the variables will
not be available unless you declare them global (which kinda makes the
function pointless).
Any ideas?
-Jason Garber
IonZoft.com
At 06:55 PM 11/18/2001 -0500, Joe Stump wrote:
>You may want to do something like this instead:
>
><?
>
> function my_extract($arr)
> {
> if(is_array($arr) && sizeof($arr))
> {
> while(list($key,$val) = each($arr)
> {
> $new_var = str_replace(' ','_',$key);
> global $$new_var;
> $$new_var = $val;
> }
> }
> }
>
>?>
>
>--Joe
>
>
>On Sun, Nov 18, 2001 at 04:21:46PM -0500, David Bernier wrote:
> > There is this array which I would like to convert into a series
> variables using the extract function:
> >
> > <?
> > $oz = array(
> > "lion" => "courage",
> > "dorothy" => "kansas",
> > "scarecrow" => "brain"
> > "tin man" => "heart");
> >
> > extract($oz);
> > ?>
> >
> > now, I would like to access my new variables. it is obviously easy for
> $lion, $dorothy, and $scarecrow but it isn't for "tin man".
> >
> > from this, I have 3 or 4 questions:
> > 1) has $oz["tin man"] been passed into a variable?
> > 2) if yes, how do I access the variable that came out of $oz["tin man"]?
> > 3) let's pretend that I have no control over the names of the keys for
> $oz, how should I have called extract() to tell it to replace the space
> between "tin" and "man" by a underscore character?
> > 4) finally, is there a way to access and retrieve that values of the
> symbol table without knowing their names?
> >
> > David
> >
>
>Joe Stump <[EMAIL PROTECTED]>
>------------------------------------------------------------------------
>"How would this sentence be different if pi equaled 3?"
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