In the include file, call it """,
<? $db_name  =  "database_name";

and then at the top of a page needing the database ...
require( "" );
$db = mysql_pconnect("$db_server","$db_user", "$db_password");
// and then proceed with the rest of the page.
// look at the manual for examples
// adding "or die("Could not connect to server") " to the mysql_pconnect is 
a good idea, as the script stops there if the connection fails, rather than 
printing out all your source with a pile of error messages.

Miles Thompson

At 03:52 PM 11/29/2001 +0100, Tommy Straetemans wrote:
>I'am totaly new in php i work always with asp.
>I give the folowing hidden fields to a php script
><input type=hidden name=connectie value="">
><input type=hidden name=uid value="U0498526">
><input type=hidden name=pwd value="iwinfo59">
><input type=hidden name=database value="D0498526">
>and in my php script i try to make my connection as follows:
>$conn = mysql_connect('%s','%s','%s',$connectie,$uid,$pwd);
>but i keep getting this error:
>Warning: Wrong parameter count for mysql_connect() in
>/home/users/ on line 27
>What do i wrong or is there a method to make my connection with a include
>Tommy Straetemans
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