In the include file, call it ""dbname.inc",
<? $db_name = "database_name";
$db_server="Server_name";
$db_user="name";
$db_password="password"?>
and then at the top of a page needing the database ...
<?
require( "dbname.inc" );
$db = mysql_pconnect("$db_server","$db_user", "$db_password");
mysql_select_db("$db_name",$db);
// and then proceed with the rest of the page.
// look at the manual for examples
// adding "or die("Could not connect to server") " to the mysql_pconnect is
a good idea, as the script stops there if the connection fails, rather than
printing out all your source with a pile of error messages.
Miles Thompson
At 03:52 PM 11/29/2001 +0100, Tommy Straetemans wrote:
>Hi
>
>I'am totaly new in php i work always with asp.
>I give the folowing hidden fields to a php script
><input type=hidden name=connectie value="mysqlhost.mijndomein.be:3306">
><input type=hidden name=uid value="U0498526">
><input type=hidden name=pwd value="iwinfo59">
><input type=hidden name=database value="D0498526">
>
>and in my php script i try to make my connection as follows:
>
>$conn = mysql_connect('%s','%s','%s',$connectie,$uid,$pwd);
>mysql_select_db('%s',$database,$conn);
>
>but i keep getting this error:
>Warning: Wrong parameter count for mysql_connect() in
>/home/users/mijndomein.be/admin/x.php on line 27
>
>What do i wrong or is there a method to make my connection with a include
>file?
>
>
>
>
>Tommy Straetemans
>
>
>
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