$conn = mysql_connect($connectie,$uid,$pwd);
mysql_select_db($database,$conn);

%s is used in printf, sprintf

Regards,
Andrey Hristov
IcyGEN Corporation
http://www.icygen.com
BALANCED SOLUTIONS


----- Original Message ----- 
From: "Tommy Straetemans" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, November 29, 2001 4:52 PM
Subject: [PHP] database conection (newby)


> Hi
> 
> I'am totaly new in php i work always with asp.
> I give the folowing hidden fields to a php script
> <input type=hidden name=connectie value="mysqlhost.mijndomein.be:3306">
> <input type=hidden name=uid value="U0498526">
> <input type=hidden name=pwd value="iwinfo59">
> <input type=hidden name=database value="D0498526">
> 
> and in my php script i try to make my connection as follows:
> 
> $conn = mysql_connect('%s','%s','%s',$connectie,$uid,$pwd);
> mysql_select_db('%s',$database,$conn);
> 
> but i keep getting this error:
> Warning: Wrong parameter count for mysql_connect() in
> /home/users/mijndomein.be/admin/x.php on line 27
> 
> What do i wrong or is there a method to make my connection with a include
> file?
> 
> 
> 
> 
> Tommy Straetemans
> 
> 
> 
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