In article <[EMAIL PROTECTED]>,
 [EMAIL PROTECTED] (Christian Blichmann) wrote:

> "Cc Zona" <[EMAIL PROTECTED]> wrote in message
> > You can look over the environment vars available to you with a quick call
> > to phpinfo() <>.
> Thanks for replying, but as Philip stated in his reply to my question
> its that the actual location doesn't appear in the environment block.

That's true, the URL does not appear there as a single preset variable; 
it's up to you to re-assemble a URL out of the variables that are 
available, and thus the need to scan the vars phpinfo() has to offer.  
Since you're using PHP as a CGI, somewhat different variables get set than 
when PHP is run as a module, so a call to phpinfo() is the best way to 
identify the right vars for accomplishing your task.

Question: before you dismissed phpinfo() as useless, did you call it and 
look at what's there?  Because more than likely the info that you envision 
extracting in a two step process (access URL, break down into needed 
components) can be directly accessed from one or more environment/server 


PHP General Mailing List (
To unsubscribe, visit:

Reply via email to