I don't know if it helps you, but normally you have to quote the
variable in the SQL-Statement like:
SELECT * FROM sessions WHERE sessionID = '$sessionID'
Otherwise I always get an SQL-Error
Jean-Marc Godart wrote:
> Hello everyone,
> I am a new PHP user, from Belgium. I am trying to manage a MySQL database with PHP,
>and I kindly request your help to solve a little (probably very stupid) problem I
>have been dealing with for a while already ...
> I have a MySQL database (called "sessions") with a auto-increment INT field called
>"sessionID". I try to check if there is already a record in this database with a
>given sessionID, which is called $sessionID in PHP. I use this query, which must be
>wrong (but I cannot find out why !!!) :
> SELECT * FROM sessions WHERE sessionID = $sessionID
> Even though there is already a record with the right sessionID, my program does not
>find it (I always get 0 when using mysql_num_rows() after the query). Though, if I
>replace "$sessionID" by, for example 4, then that works and it says there is already
>a record with that ID.
> I guess the problem comes from comparing two different kinds of variables, but I
>can't fix it ... Could anyone please help ? By advance, thank you !!!
> Best regards from Belgium,
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