I think the random number query will work but I have a problem with the context of the echo line.
Here's how I get the image path. <? $root_path = "/www/special_projects/Elkhart"; $agent_url = "$root_path/$agent_name"; ?> <img src="<? echo $agent_url; ?>"> How would I use the rand function in the above statement? Ed > When you create the src tag in for the image, add a random number query > string - that will cause the browser to request the image instead of > using the cached version. I.e... > > echo '<img src="/images/image.jpg?'.rand(1000,9999).'">'; > > -- > Stuart > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
