I get an error with this. PHP doesn't like "$name$i".
for ($i = 1; $i <= 3; $i++) {
$arr_name[$i] = $name$i; // I want $name1,$name2,$name3 etc....
}
I've looked at Variable variables but I don't think that is what I need.
What about if I wanted something like
$name_1_ff
$name_2_ff
$name_3_ff
neither of these work.
$name_$i_ff
$name_.$i._ff
Having something after causing more of a problem. First of all PHP can't
find the value of "$name_" and "_ff" just breaks it more.
Jeff
----- Original Message -----
From: "Rick Emery" <[EMAIL PROTECTED]>
To: "Jeff Pauls" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, February 25, 2003 3:26 PM
Subject: Re: [PHP] Auto Incrementing a Variable name?
> You're on the right track:
> for ($i = 1; $i <= 3; $i++) {
> $arr_name[$i] = $name$i; // I want $name1,$name2,$name3 etc....
> }
>
> ----- Original Message -----
> From: "Jeff Pauls" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, February 25, 2003 3:18 PM
> Subject: [PHP] Auto Incrementing a Variable name?
>
>
> Hi,
> I've been playing with this for a while now. Say I had the following
variables:
>
> $name1 = "joe";
> $name2 = "janis";
> $name3 = "joanne";
>
> Is there a way in php to increment the variable name not the value?
Something like this....
>
> for ($i = 1; $i <= 3; $i++) {
> $arr_name[$i] = $name.$i; // I want $name1,$name2,$name3 etc....
> }
>
>
> This way say if I had 500 database queries that need to be updated I could
just loop through each
> and just change the record id.....
>
> for ($i = 1; $i <= 500; $i++) {
>
> $query_update = "UPDATE table SET name=' $arr_name[$i]', WHERE
person_id='$i";
> $result_update = mysql_query($query_update) or die("Query failed");
> }
>
> instead of doing something like this:
>
> $query_update1 = "UPDATE table SET name=' $name1', WHERE person_id='1";
> $result_update1 = mysql_query($query_update1) or die("Query failed");
>
> $query_update2 = "UPDATE table SET name=' $name2', WHERE person_id='2";
> $result_update2 = mysql_query($query_update2) or die("Query failed");
>
> $query_update3 = "UPDATE table SET name=' $name3', WHERE person_id='3";
> $result_update3 = mysql_query($query_update3) or die("Query failed");
>
> etc.....
>
> Anybody? There has to be a way of doing this...
>
> Thanks,
>
> Jeff
>
>
>
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