Re: [PHP] Auto Incrementing a Variable name?

[John Nichel]

Jeff Pauls wrote:
I get an error with this. PHP doesn't like "$name$i".

for ($i = 1; $i <= 3; $i++)  {
     $arr_name[$i] = $name$i;         // I want $name1,$name2,$name3 etc....
}
Try $arr_name[$i] = $name . $i;

 I've looked at Variable variables but I don't think that is what I need.
What about if I wanted something like
$name_1_ff
$name_2_ff
$name_3_ff
neither of these  work.

 $name_$i_ff
 $name_.$i._ff
Try  $name . "_" . $i . "_ff";

Having something after causing more of a problem. First of all PHP can't
find the value of "$name_" and "_ff" just breaks it more.
Jeff

----- Original Message -----
From: "Rick Emery" <[EMAIL PROTECTED]>
To: "Jeff Pauls" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, February 25, 2003 3:26 PM
Subject: Re: [PHP] Auto Incrementing a Variable name?


You're on the right track:
for ($i = 1; $i <= 3; $i++)  {
$arr_name[$i] = $name$i;         // I want $name1,$name2,$name3 etc....
}
----- Original Message -----
From: "Jeff Pauls" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, February 25, 2003 3:18 PM
Subject: [PHP] Auto Incrementing a Variable name?
Hi,
I've been playing with this for a while now. Say I had the following
variables:

$name1 = "joe";
$name2 = "janis";
$name3 = "joanne";
Is there a way in php to increment the variable name not the value?
Something like this....

for ($i = 1; $i <= 3; $i++)  {
$arr_name[$i] = $name.$i;         // I want $name1,$name2,$name3 etc....
}
This way say if I had 500 database queries that need to be updated I could
just loop through each

and just change the record id.....

for ($i = 1; $i <= 500; $i++)  {

$query_update = "UPDATE table SET name=' $arr_name[$i]',  WHERE
person_id='$i";

$result_update = mysql_query($query_update) or die("Query failed");
}
instead of doing something like this:

$query_update1 = "UPDATE table SET name=' $name1',  WHERE person_id='1";
$result_update1 = mysql_query($query_update1) or die("Query failed");
$query_update2 = "UPDATE table SET name=' $name2',  WHERE person_id='2";
$result_update2 = mysql_query($query_update2) or die("Query failed");
$query_update3 = "UPDATE table SET name=' $name3',  WHERE person_id='3";
$result_update3 = mysql_query($query_update3) or die("Query failed");
etc.....

Anybody? There has to be a way of doing this...

Thanks,

Jeff









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