Should be: ${name$i}
Jeff Pauls wrote:
I get an error with this. PHP doesn't like "$name$i".
for ($i = 1; $i <= 3; $i++) { $arr_name[$i] = $name$i; // I want $name1,$name2,$name3 etc.... }
I've looked at Variable variables but I don't think that is what I need. What about if I wanted something like
$name_1_ff $name_2_ff $name_3_ff
neither of these work.
$name_$i_ff $name_.$i._ff
Having something after causing more of a problem. First of all PHP can't find the value of "$name_" and "_ff" just breaks it more.
Jeff
----- Original Message ----- From: "Rick Emery" <[EMAIL PROTECTED]> To: "Jeff Pauls" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Tuesday, February 25, 2003 3:26 PM Subject: Re: [PHP] Auto Incrementing a Variable name?
variables:You're on the right track: for ($i = 1; $i <= 3; $i++) { $arr_name[$i] = $name$i; // I want $name1,$name2,$name3 etc.... }
----- Original Message ----- From: "Jeff Pauls" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, February 25, 2003 3:18 PM Subject: [PHP] Auto Incrementing a Variable name?
Hi,
I've been playing with this for a while now. Say I had the following
Something like this....$name1 = "joe"; $name2 = "janis"; $name3 = "joanne";
Is there a way in php to increment the variable name not the value?
just loop through eachfor ($i = 1; $i <= 3; $i++) { $arr_name[$i] = $name.$i; // I want $name1,$name2,$name3 etc.... }
This way say if I had 500 database queries that need to be updated I could
and just change the record id.....person_id='$i";
for ($i = 1; $i <= 500; $i++) {
$query_update = "UPDATE table SET name=' $arr_name[$i]', WHERE
$result_update = mysql_query($query_update) or die("Query failed"); }
instead of doing something like this:
$query_update1 = "UPDATE table SET name=' $name1', WHERE person_id='1"; $result_update1 = mysql_query($query_update1) or die("Query failed");
$query_update2 = "UPDATE table SET name=' $name2', WHERE person_id='2"; $result_update2 = mysql_query($query_update2) or die("Query failed");
$query_update3 = "UPDATE table SET name=' $name3', WHERE person_id='3"; $result_update3 = mysql_query($query_update3) or die("Query failed");
etc.....
Anybody? There has to be a way of doing this...
Thanks,
Jeff
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