On 9/25/07, Krzysztof Kowalczyk <[EMAIL PROTECTED]> wrote:
> Reverted. Sorry about that and thanks for noticing and explanation.
Thanks, quick response :)
> I have to say that I still don't get that code. Before making this
> change I wrote a test program (see below) that ran the expression in
> question (a * (int) b / b != a) on every integer and would say if for
> any int a the result is any different than just testing for a < 0.
Try this one:
#include <stdio.h>
int main(int argc, char *argv[])
{
int a = (1 << 16) + 5, b = (1 << 16) + 17;
printf("a = %d, b = %d, a * b = %d, a * b / b = %d\n",
a, b, a * b, a * b / b);
return 0;
}
cheers,
Kristian
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