Something like this?
dDate = ctod('2/28/'+<year as a string>) + 1
if month(dDate) = 2
' leap year
Else
' not leap year
Endif
Lou
-----Original Message-----
From: [email protected] [mailto:[email protected]] On
Behalf Of MB Software Solutions, LLC
Sent: Tuesday, April 12, 2011 2:49 PM
To: [email protected]
Subject: Testing for leap year?
How do you test to see if it's a leap year? The first thing that comes
to my mind is checking to see if DATE(nCurrentYearVariable,2,29) throws
an error or not. e.g.
dDate = DATE(nCurrentYearVariable,2,29)
lLeapYear = not empty(dDate)
Better ideas?
--
Mike Babcock, MCP
MB Software Solutions, LLC
President, Chief Software Architect
http://mbsoftwaresolutions.com
http://fabmate.com
http://twitter.com/mbabcock16
[excessive quoting removed by server]
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