On 4/12/11 2:49 PM, Lou Syracuse wrote:
> Something like this?
>
> dDate = ctod('2/28/'+<year as a string>) + 1
> if month(dDate) = 2
> ' leap year
> Else
> ' not leap year
> Endif
It isn't as simple as that. Here's the pseudocode algorithm from wikipedia:
if year modulo 400 is 0
then is_leap_year
else if year modulo 100 is 0
then not_leap_year
else if year modulo 4 is 0
then is_leap_year
else
not_leap_year
But I like Mike's TRY/CATCH approach.
Paul
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