This is very neat, Raul. Thanks. Kip Murray
Sent from my iPad On Jan 15, 2013, at 7:12 AM, Raul Miller <rauldmil...@gmail.com> wrote: > It's easy because isHermitian is so close to what you need for hft. > In other words, hft=: -:@+ |: almost works, but it should only reduce > the diagonal by half, not the rest of it. hft=: (% 1 + =@i.@#)@:+ > +@|: is more complicated but structurally similar. > > FYI, > > -- > Raul > > On Tue, Jan 15, 2013 at 8:05 AM, Aai <agroeneveld...@gmail.com> wrote: >> Why is it easy? From the point of view of a mathematician perhaps. I just >> experimented towards the desired result. >> >> ishermitian ((]+[*~:) +@|:) A >> 1 >> ishermitian (+ +@|: * >/~@i.@#) A >> 1 >> >> >> >> On 15-01-13 11:25, km wrote: >>> >>> This is an easy one. A Hermitian matrix matches its conjugate transpose. >>> Write a verb hft that creates a Hermitian matrix from a triangular one that >>> has a real diagonal. >>> >>> ishermitian =: -: +@|: >>> ]A =: 2 2 $ 1 2j3 0 4 >>> 1 2j3 >>> 0 4 >>> ]B =: hft A >>> 1 2j3 >>> 2j_3 4 >>> ishermitian A >>> 0 >>> ishermitian B >>> 1 >>> >>> Kip Murray >>> >>> Sent from my iPad >>> ---------------------------------------------------------------------- >>> For information about J forums seehttp://www.jsoftware.com/forums.htm >> >> >> -- >> Met vriendelijke groet, >> @@i = Arie Groeneveld >> >> >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
