I finally got an hft that pleases me:
]A=:2 2$1 2j3 0 4
1 2j3
0 4
hftla
] + (0 = ]) * [: + |:
hftla A
1 2j3
2j_3 4
Kip, Is there a good matrix with shape 3 3 to use for testing?
Linda
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of km
pSent: Thursday, January 17, 2013 4:35 PM
To: [email protected]
Subject: Re: [Jprogramming] Hermitian from triangular
Yep, archangel.
Sent from my iPad
On Jan 17, 2013, at 2:51 PM, bob therriault <[email protected]> wrote:
> Last tweak (I promise)
>
> Because the rank of | is 0 0 0 we don't need to specify the rank in the
definition of la.
>
> la =: [`]@.(<&|)
> (la +@|:) A
> 1 2j3
> 2j_3 4
>
> Though we do need the parenthesis to separate < from the @. conjunction.
>
> Cheers, bob
>
>
> On 2013-01-17, at 12:29 PM, bob therriault wrote:
>
>> la =: [`]@.(<&|)"0
>
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