Negative zero, eh? Tried it once; didn't like it. Stay away from negative zero. You are *that* close to NaN (and hence eternal damnation).
On Wed, Jan 16, 2013 at 4:26 AM, Henry Rich <henryhr...@nc.rr.com> wrote: > On my awaking, there was a whiff of sulfur in the air, and a greenish > haze... and somehow in my mind the idea that that last program won't work, > because of the possibility of negative zero. I'll stay relegated to imp > status. > > Henry Rich > > > On 1/15/2013 6:20 PM, Henry Rich wrote: > >> Nah, that's not beyond impish. The devilish solution is to take the >> bitwise OR of the matrix with its conjugate transpose (but that's easier >> in assembler language than in J: >> (23 b.&.(a.&i.)&.(2&(3!:5))&.+. +@|:)) >> ). And you need to be sure that the zeros on the lower diagonal and >> below are true zeros! >> >> Henry Rich >> >> On 1/15/2013 6:03 PM, km wrote: >> >>> Oh, boy! (v1`v2) } y <--> (v1 y) } (v2 y) >>> >>> Brief and devilish, take care for your soul, Henry! >>> >>> --Kip >>> >> ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
