This looks nice. For testing I like
]B =: 3 3 $ 0 _1j2 0 0 _3 4j_5 0 0 6
0 _1j2 0
0 _3 4j_5
0 0 6
Kip
Sent from my iPad
On Jan 18, 2013, at 3:49 AM, "Linda Alvord" <lindaalv...@verizon.net> wrote:
> I finally got an hft that pleases me:
>
> ]A=:2 2$1 2j3 0 4
> 1 2j3
> 0 4
>
> hftla
> ] + (0 = ]) * [: + |:
>
> hftla A
> 1 2j3
> 2j_3 4
>
> Kip, Is there a good matrix with shape 3 3 to use for testing?
>
> Linda
>
>
> -----Original Message-----
> From: programming-boun...@forums.jsoftware.com
> [mailto:programming-boun...@forums.jsoftware.com] On Behalf Of km
> pSent: Thursday, January 17, 2013 4:35 PM
> To: programm...@jsoftware.com
> Subject: Re: [Jprogramming] Hermitian from triangular
>
> Yep, archangel.
>
> Sent from my iPad
>
>
> On Jan 17, 2013, at 2:51 PM, bob therriault <bobtherria...@mac.com> wrote:
>
>> Last tweak (I promise)
>>
>> Because the rank of | is 0 0 0 we don't need to specify the rank in the
> definition of la.
>>
>> la =: [`]@.(<&|)
>> (la +@|:) A
>> 1 2j3
>> 2j_3 4
>>
>> Though we do need the parenthesis to separate < from the @. conjunction.
>>
>> Cheers, bob
>>
>>
>> On 2013-01-17, at 12:29 PM, bob therriault wrote:
>>
>>> la =: [`]@.(<&|)"0
>>
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