I think 0"_1 b. 0 _
I think that result should be _1 _1 _1 -- Raul On Sun, Jun 2, 2013 at 5:03 PM, Henry Rich <[email protected]> wrote: > Thw way dissect knows the rank of the verb it is executing is by replacing > avg with > > (verbex_123_ =: avg) > > and then doing verbex b. 0 to see what rank was really used. I had to do it > this way to handle the case of u"v . > > I won't find a negative rank that way, but I think the only way a negative > rank can be assigned is using " , so I plan to look at the trailing tokens > of the first line of the definition of a verb, and see if they are " numeric > or ( " numeric ) and detect negative rank that way. But I don't do that yet > - I just treat negative rank as infinite rank. > > > Henry Rich > > On 6/2/2013 9:32 AM, Raul Miller wrote: >> >> I am trying to understand how ds (dissect.ijs addon) works >> >> So I define a name with a rank, and ds properly shows that rank >> avg=:(+/ %#)"1 >> ds 'avg p: i. 3 4' >> >> And, I can take the definition of ds and plug it in, and that works >> the same way: >> ds >> [: ([: (display_dissect_) 0:@". ::1:)`>@.(32 = 3!:0) [: >> (parse_dissect_) 0&# :[ (([ ; 18!:5@(''"_) ; ]) , >> z458095869_dissectnopath_@(''"_)) ] >> >> ([: ([: (display_dissect_) 0:@". ::1:)`>@.(32 = 3!:0) [: >> (parse_dissect_) 0&# :[ (([ ; 18!:5@(''"_) ; ]) , >> z458095869_dissectnopath_@(''"_)) ]) 'avg p: i. 3 4' >> >> But when I try to get the result that has the rank of the name that I >> defined, that is empty: >> >> $z458095869_dissectnopath_'' >> 0 3 >> >> But if I fix the definition, it works fine: >> >> $z458095869_dissectnopath_ f.'' >> 11 3 >> >> What's going on here? >> >> Thanks, >> > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
