I believe the table adverb assumes that the verb has rank 0.  If it does
not, then you get a mess.  Y'know: GIGO.


On Fri, May 9, 2014 at 10:10 AM, Kip Murray <[email protected]> wrote:

> Agreed, but can the result from rank infinity (+ %) be understood?
>
> On Friday, May 9, 2014, Roger Hui <[email protected]> wrote:
>
> > rank 0.
> >
> >
> >
> > On Fri, May 9, 2014 at 10:05 AM, Kip Murray <[email protected]
> <javascript:;>>
> > wrote:
> >
> > > Here is a verb that defeats the system's table adverb.  What is going
> on?
> > >
> > >    table
> > > 1 : (':'; '(((#~LF-.@e.])5!:5<''u'');,.y),.({.;}.)":x,y u/x')~
> > >
> > >    0 1 2 3 (+ %) table 0 1 2 3  NB. misbehaves
> > > +---+----------------------+
> > > |+ %|0                     |
> > > +---+----------------------+
> > > |0  | 1 2 3 _ 2 2.5 3.33333|
> > > |1  |                      |
> > > |2  |                      |
> > > |3  |                      |
> > > +---+----------------------+
> > >
> > >    0 1 2 3 % table 0 1 2 3  NB. normal behavior
> > > +-+----------------+
> > > |%|0 1   2        3|
> > > +-+----------------+
> > > |0|0 0   0        0|
> > > |1|_ 1 0.5 0.333333|
> > > |2|_ 2   1 0.666667|
> > > |3|_ 3 1.5        1|
> > > +-+----------------+
> > >
> > > --Kip Murray
> > >
> > >
> > >
> > > --
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