Try this:
3 5 5 #: i. 3 5 5
Then try this:
1 {"1 (3 5 5 #: i. 3 5 5)
Then try this:
#:"#:
I hope that helps,
Thanks,
--
Raul
On Fri, Jun 10, 2016 at 6:38 AM, Martin Kreuzer <[email protected]> wrote:
> Raul -
>
> Following this thread, I managed to grasp (reproduce) the expression (0 2 1
> |: 3 5 5 $ i. 5) which Bo found satisfactory.
>
> Challenged by your remark "But probably no easier to read." I have tried to
> sort of reconstruct your approach:
>
> First I read up on dyadic Antibase (x #: y) and found the remainder example;
> thus
>
> > ,(i. 10) ;(5 #: i. 10)
> 0 1 2 3 4 5 6 7 8 9
> 0 1 2 3 4 0 1 2 3 4
>
> Producing this square matrix
>
> i. 5 5
> 0 1 2 3 4
> 5 6 7 8 9
> 10 11 12 13 14
> 15 16 17 18 19
> 20 21 22 23 24
>
> and applying the above I got
>
> 5 #: i. 5 5
> 0 1 2 3 4
> 0 1 2 3 4
> 0 1 2 3 4
> 0 1 2 3 4
> 0 1 2 3 4
>
> and (5 #: i. 3 5 5) got me three blocks of those.
>
> Changing the axis preference (?) switched rows and columns
>
> 1 0 |: 5 #: i. 5 5
> 0 0 0 0 0
> 1 1 1 1 1
> 2 2 2 2 2
> 3 3 3 3 3
> 4 4 4 4 4
>
> and in the case of the three blocks this would be written as (0 2 1 |: 5 #:
> i. 3 5 5) as the number of blocks remains untouched.
>
> What seemed to me a shortcut for the special case of a three-dimensinal
> arrangement of square matrices this gives the same result:
>
> 1 |: 5 #: i. 3 5 5
> 0 0 0 0 0
> 1 1 1 1 1
> 2 2 2 2 2
> 3 3 3 3 3
> 4 4 4 4 4
>
> 0 0 0 0 0
> 1 1 1 1 1
> 2 2 2 2 2
> 3 3 3 3 3
> 4 4 4 4 4
>
> 0 0 0 0 0
> 1 1 1 1 1
> 2 2 2 2 2
> 3 3 3 3 3
> 4 4 4 4 4
>
> Using brackets I could write that as
> (1 |: 5 #: i.) 3 5 5
> replacing the (5) by grabbing it from the list like (1 { 3 5 5)
> I continued to
> (1 |: 1 & { #: i.) 3 5 5
> which looked promising.
>
> It looked to me as you were taking advantage of the (1) being mentioned
> there twice and therefore combining, but ...
> Q: Could you enlighten me on this final step..?
>
> Thanks
> -M
>
>
>
>
> At 2016-06-10 06:51, you wrote:
>>
>> I just stumbled across this. It occurs to me that (1&{@#:i.)3 5 5 would
>> be one character shorter. But probably no easier to read. Thanks, -- Raul On
>> Wed, Jun 8, 2016 at 5:31 PM, 'Bo Jacoby' via Programming
>> <[email protected]> wrote: > Thanks everyone! > This: > 0 2 1|:3
>> 5 5$i.5 > > produces what I wanted. > The result is however destroyed in the
>> process of emailing it to [email protected] . Line feeds are
>> deleted. I don't know why. > Problem is solved. Thanks again. > Bo. > >
>> Den 21:10 onsdag den 8. juni 2016 skrev Cliff Reiter
>> <[email protected]>: > > > > Or > ,./": 3 5$"1 0 i.5 > > 0 0 0 0 01 1 1
>> 1 12 2 2 2 23 3 3 3 34 4 4 4 4 > > 0 0 0 0 01 1 1 1 12 2 2 2 23 3 3 3 34 4 4
>> 4 4 > > 0 0 0 0 01 1 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4 > > But a strange
>> thing to want to build. > > On 6/8/2016 1:37 PM, robert therriault wrote: >>
>> Maybe this? >> >> 5( 3 # ,:@,@":@:(#/"0)) i. 5 >> 0 0 0 0 01 1 1 1 12
>> 2 2 2 23 3 3 3 34 4 4 4 4 >> 0 0 0 0 01 1 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4
>> >> 0 0 0 0 01 1 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4 >> >> But I am confused as
>> well about the request for a shape 3 5 5 of what appears as a shape 3 45
>> literal matrix. I do have '01' in mine though. :-) >> >> Cheers, bob >> >>>
>> On Jun 8, 2016, at 10:29 AM, Raul Miller <[email protected]> wrote: >>>
>> >>> Did you mean something like this? >>> >>> (<.0.8*1+i.25) 10&#./."1]
>> 3#,:5# i.5 >>> 0 0 0 0 1 1 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4 >>> 0 0 0 0 1 1
>> 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4 >>> 0 0 0 0 1 1 1 1 12 2 2 2 23 3 3 3 34 4
>> 4 4 4 >>> >>> Except, that doesn't get you those leading zeros for the '01'
>> column, >>> so maybe instead it needs to be character? >>> >>> But a
>> character array would not have anything to do with that 3 5 5 >>> shape you
>> suggested, so for that, and guessing what you want, maybe it >>> should be
>> something like this? >>> >>> <.25%~i.3 5 5 >>> 0 0 0 0 0 >>> 0 0 0 0 0
>> >>> 0 0 0 0 0 >>> 0 0 0 0 0 >>> 0 0 0 0 0 >>> >>> 1 1 1 1 1 >>> 1 1 1 1 1
>> >>> 1 1 1 1 1 >>> 1 1 1 1 1 >>> 1 1 1 1 1 >>> >>> 2 2 2 2 2 >>> 2 2 2 2 2
>> >>> 2 2 2 2 2 >>> 2 2 2 2 2 >>> 2 2 2 2 2 >>> >>> Except that that doesn't
>> look at all like what you asked for. A 5 3 4 >>> shape gets a little closer:
>> >>> >>> <.12%~i.5 3 4 >>> 0 0 0 0 >>> 0 0 0 0 >>> 0 0 0 0 >>> >>> 1 1 1 1
>> >>> 1 1 1 1 >>> 1 1 1 1 >>> >>> 2 2 2 2 >>> 2 2 2 2 >>> 2 2 2 2 >>> >>> 3 3
>> 3 3 >>> 3 3 3 3 >>> 3 3 3 3 >>> >>> 4 4 4 4 >>> 4 4 4 4 >>> 4 4 4 4 >>> >>>
>> But all of these have conflicts with some aspect of your original >>>
>> request, and I can't figure out what it is that you really wanted. >>> >>> I
>> hope this helps? >>> >>> Thanks, >>> >>> -- >>> Raul >>> >>> >>> On Wed, Jun
>> 8, 2016 at 5:22 AM, 'Bo Jacoby' via Programming >>>
>> <[email protected]> wrote: >>>> Dear J'ers. >>>> Please tell me how
>> to program the 3 5 5 array below. >>>> I am experimenting rather than
>> understanding. I expect the answer to be quite elementary. >>>> Thanks! Bo.
>> >>>> >>>> 0 0 0 0 01 1 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4 >>>> 0 0 0 0 01 1 1
>> 1 12 2 2 2 23 3 3 3 34 4 4 4 4 >>>> 0 0 0 0 01 1 1 1 12 2 2 2 23 3 3 3 34 4
>> 4 4 4 >>>> >>>>
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