You are using the verb (monad }). You need (dyad }).
Henry Rich
On 1/5/2017 8:16 PM, Moon S wrote:
Hm, and v0`v1`v2 has some quirks...
v0=:_1 1&*@{. NB. head item, multiplied by _1 1
v1=:_2&{. NB. two last items show the place where to put the above
v2=:0 0 0 0"_ NB. initial vector
v0 5 2 3
_5 5
v1 5 2 3
2 3
v2 5 2 3
0 0 0 0
(_5 5)(2 3) } (0 0 0 0) NB. as nouns, this all works
0 0 _5 5
v0`v1`v2} 5 2 3
|rank error
Even simpler example misbehaves:
5 (2}) 1 1 1 1
1 1 5 1
(5*]) 1
5
(2*]) 1
2
(4#]) 1
1 1 1 1
((5*])`(2*])`(4#]) }) 1 NB. ???
1
On Fri, Jan 6, 2017 at 2:29 AM, 'Pascal Jasmin' via Programming
<[email protected]> wrote:
(+/)`%`# 1 : ' ''`f g h'' =. m label_. (f g h) f.'
+/ % #
----- Original Message -----
From: Moon S <[email protected]>
To: programming <[email protected]>
Sent: Thursday, January 5, 2017 7:26 PM
Subject: Re: [Jprogramming] Tacit definition involving adverb argument
Ah! The special form for }
x (v0`v1`v2)} y
Great!
What about a user-defined adverb? If I define an adverb to pretend I
can have three parameters.
On Fri, Jan 6, 2017 at 1:53 AM, 'Pascal Jasmin' via Programming
<[email protected]> wrote:
11 22 33&( 0:`(<:@])`[}) 2
11 0 33
----- Original Message -----
From: Moon S <[email protected]>
To: programming <[email protected]>
Sent: Thursday, January 5, 2017 6:36 PM
Subject: [Jprogramming] Tacit definition involving adverb argument
Is there a tacit definition of such a verb? Is there a way to pass a
value to the adverb?
f =: 3 : '0 (<:y)} 11 22 33'
f 1
0 22 33
f 2
11 0 33
PS. Also, I couldn't suspect that besides a usual definition of dyad
adverb such as
1 : ('';':';'...x...m...y...') NB. explicit defs inside
there's also a shorter way:
1 : '...[...x...]...' NB. tacit defs inside
Of course the reading of The Phrases is very useful... but so hard!
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