> R =: ((cos , -@sin) ,: sin , cos) I am curious why the definition isn't
(cos , -@sin) ,: (sin , cos) It seems prettier (more balanced, more symmetric). On Fri, Dec 18, 2020 at 3:56 AM Ben Gorte <bgo...@gmail.com> wrote: > Perhaps I'm missing the point, but I would say: > > R =: ((cos , -@sin) ,: sin , cos) > > R 1r6p1 > > 0.866025 _0.5 > > 0.5 0.866025 > > > Ben > > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
