Bill: All the eigenvectors are for the matrix operating on the left. We have found v such that Av=lv, where A is the matrix and l is the eigenvalue. You need to premultiply v by A and then divide.
Best wishes, John Bill Harris wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > Just curious: given the principal eigenvector by the power method, would > it be appropriate to calculate the associated eigenvalue by > postmultiplying the eigenvector by the original matrix and then dividing > (say) the first element of that new vector by the first element of the > principal eigenvector? > > I did that with John's approach last night and got a principal > eigenvalue around 5 for Coyle's 4x4 matrix, about 20-25% high, as I > recall. I don't know if that error is due to deviations between his > eigenvector and the one John's algorithm calculated, to a numerical > error in my approach, or due to my algorithm being fundamentally flawed. > > Thanks, > > Bill > - -- > Bill Harris http://facilitatedsystems.com/weblog/ > Facilitated Systems Everett, WA 98208 USA > http://facilitatedsystems.com/ phone: +1 425 337-5541 > -----BEGIN PGP SIGNATURE----- > Version: GnuPG v1.4.1 (MingW32) > Comment: For more information, see http://www.gnupg.org > > iD8DBQFEB0EU3J3HaQTDvd8RAssjAJ9b4dHWx1IW4OvTSu7O1ou2HrqJgQCeOTR6 > EhYiKnZ0FsnMSD/lL+rtcKM= > =PXD/ > -----END PGP SIGNATURE----- > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
