There's an integer on each vertex of the pentagon. If there is a negative integer, y on one of the vertices, flanked by x and z, replace x, y, z by x+y, -y, z+y. Sum of all the numbers on the pentagon is > 0. If there is more than one negative number, pick whichever one you want. Does this procedure have to end? ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
- [Jprogramming] integers on a pentagon puzzle Miodrag Milenkovic
- Re: [Jprogramming] integers on a pentagon puzzle Devon McCormick
- Re: [Jprogramming] integers on a pentagon puzz... Miodrag Milenkovic
- Re: [Jprogramming] integers on a pentagon ... Devon McCormick
- Re: [Jprogramming] integers on a penta... Miodrag Milenkovic
- Re: [Jprogramming] integers on a ... Devon McCormick
- Re: [Jprogramming] integers o... greg heil
- Re: [Jprogramming] intege... Miodrag Milenkovic
- Re: [Jprogramming] intege... John Randall
- Re: [Jprogramming] intege... John Randall
- Re: [Jprogramming] intege... Miodrag Milenkovic
