sorry, haven't even noticed the last mistake. you can't do what you did in the last step, you can only apply a transformation centered on a negative number. in the last step you are starting with y = 1.
even though one transformation involves only three adjacent numbers, the total number of vertices does matter. On 5/25/06, Devon McCormick <[EMAIL PROTECTED]> wrote:
I only looked at three numbers because that's all you have to consider for a given transformation. Just use the other 2 numbers to make the total sum > 0, e.g. the other 2 numbers are 1 & 2. On 5/25/06, Miodrag Milenkovic <[EMAIL PROTECTED]> wrote: > > hmmm, not corresponding to the problem as stated on two counts: > > 1. there are only three numbers > 2. the sum is not > 0 > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > -- Devon McCormick ^me^ at acm. org is my preferred e-mail ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
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