t=: ('3fe',13$'f'),('3ff',13$'0'),:'3ff',(12$'0'),'1'
t
3fefffffffffffff
3ff0000000000000
3ff0000000000001
":!.18 cons"1 t
0.99999999999999989 1 1.0000000000000002
":!.18 ] 1 - cons"1 t
1.1102230246251565e_16 0 _2.2204460492503131e_16
----- Original Message -----
From: Roger Hui <[EMAIL PROTECTED]>
Date: Tuesday, April 10, 2007 8:31 am
Subject: Re: [Jprogramming] limit constants
> I usually solve such problems by working with the
> hex representation. Thus:
>
> unhex=: 3!:2
> hex =: 2&(3!:3)
> cons =: unhex @ ((}: hex 0.5)&,)
>
> ":!.18 cons (15$'0'),'1' NB. just larger than 0
> 4.9406564584124654e_324
> ":!.18 cons '3fe',13$'f' NB. just smaller than 1
> 0.99999999999999989
> ":!.18 cons '7fe',13$'f' NB. largest finite positive
> 1.7976931348623157e308
>
> Regarding the middle one, the following expressions
> show that the answer is correct:
>
> ":!.18 ] 1 - cons '3fe',13$'f'
> 1.1102230246251565e_16
> ":!.18 ] 1 - cons '3ff',13$'0'
> 0
>
>
>
> ----- Original Message -----
> From: bill lam <[EMAIL PROTECTED]>
> Date: Tuesday, April 10, 2007 3:05 am
> Subject: [Jprogramming] limit constants
>
> > Hi all,
> >
> > With respect to J's IEEE double, how to get the numbers that
> > a. just larger than 0 (smallest positive number)
> > b. just smaller than 1
> > c. largest positive number
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