On 6/1/08, Sherlock, Ric <[EMAIL PROTECTED]> wrote:
> Actually (0{ g)/1 2 3 4 or (1{g)/1 2 3 4 both work for me fine.
I think I have come up with a better way of explaining this:
When you use +`*`-/1 2 3 4, this is equivalent to
'`a b c'=: +`*`-
1 a 2 b 3 c 4
_1
When you use g/1 2 3 4 this would be equivalent to
'`a b'=: g
1 a 2 b 3 a 4
However:
'`a b'=: g
|rank error
--
Raul
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