$...@0:

?

Henry Rich

Aai wrote:
> Just guessing:
> 
> ea2=. +/@]`(*/@])`(>./@])`((i.0)"_)@.
> 
>    ;,/&.> a (~...@ea1 ([ ea2"_1 each)  ea0) b
> 52 38 30 19
> 
> BTW
> 
> Is there a better one for?
>   (i.0)"_
> 
> 
> Hallo Brian Schott, je schreef op 02-02-10 17:18:
>> Yes, that is better still.
>> Thank you.
>>
>> On Tue, Feb 2, 2010 at 10:58 AM, R.E. Boss <[email protected]> wrote:
>>   
>>> This can be simplified to
>>>
>>>   a(([: ~. ea1) (<@[ ea2"0 2 each)  ea0) b
>>> +-----------+----------+-----+
>>> |24 29 35 32|14 19 0 17|0 0 0|
>>> +-----------+----------+-----+
>>>
>>>
>>> R.E. Boss
>>>     
>> ----------------------------------------------------------------------
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>>
>>   
> 
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