h=: 13 :'+./"1 x E."1 > y'
h
[: +./"1 [ E."1 [: > ]
' ' f b NB. two spaces
0 0 0
' ' h b
1 1 0
f and what you intended for g are not equivalent. The explanation has
to do with ranks: thinking about ranks was my way of determining f and
the corrected g (named h above) are not the same.
On 11/10/2011 11:04 PM, Kip Murray wrote:
> 'a' f b
> 1 1 1
> 'a' g b
> 2 1 2
>
> In your definition of g you probably intended +. not +
>
>
> On 11/10/2011 7:36 PM, Linda Alvord wrote:
>> a=: 0 : 0
>> a is a
>> b is not a
>> c is a or not a
>> )
>> a
>> a is a
>> b is not a
>> c is a or not a
>>
>> b=:<;._2 a
>> b
>> -------T----------T---------------┐
>> │a is a│b is not a│c is a or not a│
>> L------+----------+----------------
>>
>> f=: 13 :'x&(+./@E.)&>y'
>> f
>> 4 : 'x&(+./@E.)&>y'
>>
>> 'is a' f b
>> 1 0 1
>>
>> 'not a' f b
>> 0 1 1
>>
>> Also:
>>
>> g=: 13 :'+/"1 x E."1> y'
>> g
>> [: +/"1 [ E."1 [:> ]
>>
>> 'is a' g b
>> 1 0 1
>>
>> 'not a' g b
>> 0 1 1
>>
>> Is there a way to determine if f and g are the same if they are used
>> dyadically?
>>
>>
>> -----Original Message-----
>> From: [email protected]
>> [mailto:[email protected]] On Behalf Of Roger Hui
>> Sent: Thursday, November 10, 2011 12:45 PM
>> To: Programming forum
>> Subject: Re: [Jprogramming] Boxing and Finding
>>
>> 1. t=:<;._2 s
>> 2. 'sub'&(+./@E.)&> t
>>
>>
>>
>> On Thu, Nov 10, 2011 at 9:36 AM, Skip Cave<[email protected]> wrote:
>>> Two questions,
>>>
>>> 1. I have a text array where each line is terminated with a line feed. How
>>> do you box each line of that text array to create an array of boxed text
>>> strings?
>>>
>>> 2. When you have an array of boxed text strings, how do you create a
>>> boolean array that indicates which boxes contain a particular text string?
>>>
>>> Skip
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>>>
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>>
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