Given F=: +./@E."1 S:0
   'ab cd ef' F ;: 'abcd defg zabc'
0 0 0

It's just a matter of how you form the arguments.

-- 
Raul


On Fri, Nov 11, 2011 at 3:50 PM, Kip Murray <k...@math.uh.edu> wrote:
> However,
>
>    'ab cd ef' f ;: 'abcd defg zabc'
> 0 0 0
>
> is the desired result.
>
> That is, none of the three strings 'abcd' 'defg' 'zabc' contains the
> string 'ab cd ef'
>
>    ;:'abcd defg zabc'
> +----+----+----+
> |abcd|defg|zabc|
> +----+----+----+
>
>
> On 11/11/2011 1:36 PM, Raul Miller wrote:
>> I think I would use
>>     F=: +./@E."1 S:0
>>
>>     'ab' F 'abcd'
>> 1
>>     'ab' F ;:'abcd defg zabc'
>> 1 0 1
>>     'ab cd ef' F&;: 'abcd defg zabc'
>> 1 0 0
>>
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