Hello... I appreciate the clear documentation on encoding here: https://developers.google.com/protocol-buffers/docs/encoding
However it doesn't discuss how the key/tag is encoded when the number of message types exceeds 5 bits (31). Each key in the streamed message is a varint with the value (field_number << 3) | wire_type – in other words, the last three bits of the number store the wire type. What happens if the message type is 76 for example? That is 0x4c. If the data encoding is 000 for a varint then this is just 0x0260. Is that how it is represented in the data stream? Or is it encoded like a varint which I *think* is 0xe004? Appreciate any information on this. Thanks, Ed Mazurek -- You received this message because you are subscribed to the Google Groups "Protocol Buffers" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/protobuf/0f270391-fe31-4d0d-a736-874c0520a147n%40googlegroups.com.
