Ok yes... varint wire type so the 0x4c is 0x260. then it turns into 0xe004.

Thanks,

Ed

On Friday, January 8, 2021 at 1:51:13 PM UTC-5 [email protected] wrote:

> Field number 76 with which wire type? The lowest 3 bits are the wire-type, 
> then the field number is whacked on the end. Then split into groups of 7 
> bits for varint encoding.
>
> On Fri, 8 Jan 2021, 14:05 '[email protected]' via Protocol Buffers, <
> [email protected]> wrote:
>
>> Hi Marc,
>>
>> OK thanks. 4 bits... Right. So for 76 it would look like 0xe004 in a 
>> wireshark trace ?
>>
>> Thanks,
>> Ed
>>
>> On Friday, January 8, 2021 at 8:59:52 AM UTC-5 [email protected] wrote:
>>
>>> The composed wire-type and field number are treated as a varint. And 
>>> since the MSB is reserved for continuation, after the 3-bit wire type that 
>>> only leaves 4 bits of field number, not 5, for single-byte field headers.
>>>
>>> On Fri, 8 Jan 2021, 12:47 '[email protected]' via Protocol Buffers, <
>>> [email protected]> wrote:
>>>
>>>> Hello...
>>>>
>>>> I appreciate the clear documentation on encoding here:
>>>> https://developers.google.com/protocol-buffers/docs/encoding
>>>>
>>>> However it doesn't discuss how the key/tag is encoded when the number 
>>>> of message types exceeds 5 bits (31). 
>>>>
>>>> Each key in the streamed message is a varint with the value (field_number 
>>>> << 3) | wire_type – in other words, the last three bits of the number 
>>>> store the wire type. 
>>>>
>>>> What happens if the message type is 76 for example? That is 0x4c. If 
>>>> the data encoding is 000 for a varint then this is just  0x0260. Is that 
>>>> how it is represented in the data stream? Or is it encoded like a varint 
>>>> which I *think* is 0xe004?
>>>>
>>>> Appreciate any information on this.
>>>>
>>>> Thanks,
>>>>
>>>> Ed Mazurek
>>>>
>>>> -- 
>>>> You received this message because you are subscribed to the Google 
>>>> Groups "Protocol Buffers" group.
>>>> To unsubscribe from this group and stop receiving emails from it, send 
>>>> an email to [email protected].
>>>> To view this discussion on the web visit 
>>>> https://groups.google.com/d/msgid/protobuf/0f270391-fe31-4d0d-a736-874c0520a147n%40googlegroups.com
>>>>  
>>>> <https://groups.google.com/d/msgid/protobuf/0f270391-fe31-4d0d-a736-874c0520a147n%40googlegroups.com?utm_medium=email&utm_source=footer>
>>>> .
>>>>
>>> -- 
>> You received this message because you are subscribed to the Google Groups 
>> "Protocol Buffers" group.
>> To unsubscribe from this group and stop receiving emails from it, send an 
>> email to [email protected].
>>
> To view this discussion on the web visit 
>> https://groups.google.com/d/msgid/protobuf/ed75a2d3-655f-4961-a9b8-1ad20900fa9cn%40googlegroups.com
>>  
>> <https://groups.google.com/d/msgid/protobuf/ed75a2d3-655f-4961-a9b8-1ad20900fa9cn%40googlegroups.com?utm_medium=email&utm_source=footer>
>> .
>>
>

-- 
You received this message because you are subscribed to the Google Groups 
"Protocol Buffers" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To view this discussion on the web visit 
https://groups.google.com/d/msgid/protobuf/c874576f-acae-409b-b735-5aaa445056b1n%40googlegroups.com.

Reply via email to