Hi Marc,

OK thanks. 4 bits... Right. So for 76 it would look like 0xe004 in a 
wireshark trace ?

Thanks,
Ed

On Friday, January 8, 2021 at 8:59:52 AM UTC-5 [email protected] wrote:

> The composed wire-type and field number are treated as a varint. And since 
> the MSB is reserved for continuation, after the 3-bit wire type that only 
> leaves 4 bits of field number, not 5, for single-byte field headers.
>
> On Fri, 8 Jan 2021, 12:47 '[email protected]' via Protocol Buffers, <
> [email protected]> wrote:
>
>> Hello...
>>
>> I appreciate the clear documentation on encoding here:
>> https://developers.google.com/protocol-buffers/docs/encoding
>>
>> However it doesn't discuss how the key/tag is encoded when the number of 
>> message types exceeds 5 bits (31). 
>>
>> Each key in the streamed message is a varint with the value (field_number 
>> << 3) | wire_type – in other words, the last three bits of the number 
>> store the wire type. 
>>
>> What happens if the message type is 76 for example? That is 0x4c. If the 
>> data encoding is 000 for a varint then this is just  0x0260. Is that how it 
>> is represented in the data stream? Or is it encoded like a varint which I 
>> *think* is 0xe004?
>>
>> Appreciate any information on this.
>>
>> Thanks,
>>
>> Ed Mazurek
>>
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