On 9/28/07, Yanick <[EMAIL PROTECTED]> wrote:
>
>
> var Class2 = Class.create(Class1, {
> ...
> foo: function($super, n) {
> return $super() * n;
> }
> };
new Class2().foo(2) //-> 202
You can use $super in any method, not just initialize. The public method of
"foo" still takes only 1 argument ("n") regardless of its declaration where
$super is pushed in the front. (This is a bit magical.) The special word
$super is just an implementation detail required in case you need a
reference to the overriden method.
I have a Prototype OOP tutorial ready, I just didn't publish it because
we're still deciding about the API of additional methods other than
Class.create.
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