Hi Christophe
Thanks, but is there anything more to the syntax.  Also how do you use that
optional context parameter with this within the loop and for what enhanced
value/processing does it give you?

On Mon, Apr 12, 2010 at 4:59 AM, Christophe Decaux <
christophe.dec...@gmail.com> wrote:

> If I understand well, what you're asking for is pretty close to what you
> suggested in your original post:
>
> hashToBeTested.each(function(pair){
>   if(valueToTest==pair.value){
>     hashToBeTested.unset(pair.key);
>   }
> }
>
>
> Christophe
>
> Le 10 avr. 2010 à 12:36, chrysanthe m a écrit :
>
> Hi, again
> Sorry for being obtuse.  But can someone help me and even understand how to
> write a function and call it on a hash that will take a value, compare it
> against each of the keys in the hash, on match delete the key/value, and
> return the hash.  tia.
>
> On Thu, Apr 8, 2010 at 5:24 PM, chrysanthe m <chrysant...@gmail.com>wrote:
>
>> Hi Alex
>> Thanks, but a newbie here so that was "drinking at a firehose".  Let me
>> parse it to better understand.
>> First can you really invoke on two separate enumerable objects with that
>> [n,n1,n2] syntax?  That is tremendous.
>> My problem is I need to first check the presence of a key before I unset
>> it b/c I found out unset-ing a non-existent key seems to zero the struct;
>> also it is more courteous, grin.  So how would I construct the and
>> parameterize the annonymous function to do the check and if present "do it
>> to itself".  Ideally I would like to pass in the enumerable, call the
>> function and return the modified(or not) enumerable in the function's
>> return.
>>
>> On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace <alexmlwall...@gmail.com>wrote:
>>
>>> Ah, I see. You can handle this using Enumerable's invoke. This code
>>> should make it clear:
>>>
>>> a = new Hash({ x : "foo", y : "bar" });
>>> b = new Hash({ x : "zam", y : "moof" });
>>> a.get("x");
>>>   "foo"
>>> b.get("x");
>>>   "zam"
>>> [a,b].invoke("get","x");
>>>   ["foo", "zam"]
>>> [a,b].invoke("unset","x")
>>>   ["foo", "zam"]
>>> a.get("x")
>>>   (undefined)
>>>
>>> Cheers,
>>> Alex
>>>
>>>  On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m <chrysant...@gmail.com>wrote:
>>>
>>>>  Sorry sudden send resume in this reply
>>>>
>>>> Hello
>>>> I am having a difficult time trying to enumerate a hash to determine if
>>>> a give key is in the hash and if so delete it and its value.
>>>> If I could approach it index it would be
>>>> function remove(valueToTest, hashToBeTested){
>>>>    for(i=0;i<hashToBeTested.length;i++){
>>>>       if(valueToTest==hashToBeTested[i])
>>>> hashToBeTested.unset(valueToTest);
>>>>    }
>>>>
>>>> Would I do it like
>>>>
>>>> hashToBeTested.each(function(valueToTest){
>>>>   if(valueToTest==this)hashToBeTested.unset(valueToTest);
>>>>   },hashToBeTested);
>>>> return hashToBeTested;
>>>>
>>>>
>>>> which I am sure is wrong syntactically if not semantically.  Can someone
>>>> guide the proper way and more deeply the use of this?
>>>>
>>>>
>>>> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m <chrysant...@gmail.com>wrote:
>>>>
>>>>>
>>>>>
>>>>
>>>>
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>>
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