Locally, I had to put delays on my server code to actually allow this
to be visible. Once I was convinced things were working, I removed the
delay and I don't think I ever so it now.


On 11 October 2011 15:08, Phil Petree <phil.pet...@gmail.com> wrote:
> I'm with you Richard.
>
> I have a hidden div that loads the spinner and in the AJAX onCreate I
> disable the form and unhide the div while in the  onComplete I hide the div
> and enable the form.
>
> What I have found is that if the AJAX call starts and completes quickly then
> the spinner never gets displayed as the browser is smart enough not to do
> a repaint if not needed.
>
> On Tue, Oct 11, 2011 at 7:12 AM, Richard Quadling <rquadl...@gmail.com>
> wrote:
>>
>> On 11 October 2011 00:04, nelian <i...@myskills.co.za> wrote:
>> > I am somewhat new to AJAX, but one thing that I have not touch upon is
>> > the following -
>> >
>> > When my App is making an AJAX call, from the users perspective it
>> > seems to be doing nothing, how does one go about freezing the page
>> > (Not sure what else to call it) and indicate to the user that
>> > something is happening?
>> > (I have seen it on a couple of sites, but cannot seem to find an
>> > example at the moment)
>> >
>> > Thanks in advance for the help
>> >
>> > Ian
>> >
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>> >
>>
>> I use the Ajax.Responders
>> (http://api.prototypejs.org/ajax/Ajax/Responders/) to allow me to
>> handle the creation and completion of all AJAX requests.
>>
>> In my requests, I fade in a little spinner image after 0.25s. It fades
>> out on completion.
>>
>> So, if the request is handled in handled in under 0.25s, then no spinner.
>>
>> This seems to work quite well for me.
>>
>> --
>> Richard Quadling
>> Twitter : EE : Zend : PHPDoc
>> @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea
>>
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>
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-- 
Richard Quadling
Twitter : EE : Zend : PHPDoc : Fantasy Shopper
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea :
fan.sh/6/370

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