You unsizzled my sizzle! But yeah, that will work just fine. Thanks.
On Friday, December 14, 2012 2:28:49 PM UTC-7, Jason wrote:
>
>
>
> Try it this way
>
> $('logins').select('li.seaside').invoke('show');
>
> or
>
> $('logins').select('li.fav').invoke('show');
>
> or with the variable
>
> $('logins').select('li.'+group).invoke('show');
>
>
> if you use the attribute selector instead of a class selector it
> will interpret it very literally instead of "this is what I meant"
>
> Jason Westbrook | T: 313-799-3770 | jwest...@gmail.com <javascript:>
>
>
>
> On Fri, Dec 14, 2012 at 1:10 PM, kstubs <kst...@gmail.com <javascript:>>wrote:
>
>> I have this
>>
>> $('logins').select('li[class=\'' + group + '\']').invoke('show');
>>
>>
>> This seems to be matching on an exact class name though, but I have
>> something like
>>
>>
>> <li class="seaside fav">Seaside</li>
>>
>>
>> So if group is "fav" or group is "seaside", then either should return the
>> above.
>>
>>
>> Thanks for the help.
>>
>> Karl..
>>
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