On Fri, Dec 10, 2010 at 11:36 PM, Thomas Nagy <[email protected]> wrote: > fut = concurrent.futures.ThreadPoolExecutor(max_workers=20) > for x in range(100): > # comment the following line > fut = concurrent.futures.ThreadPoolExecutor(max_workers=20) > c = counter(fut) > c.run() > """ > The runtime grows after each step: > Is there a mistake in this piece of code?
This isn't an "overhead" question, it's a "how prompt is the resource release" question. Given that you've created circular references between the futures and your counter class, the answer is probably "not prompt at all". Cheers, Nick. -- Nick Coghlan | [email protected] | Brisbane, Australia _______________________________________________ Python-Dev mailing list [email protected] http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
