I guess what I am saying is that it does not seem like I am adding any
information that is not already there when I have to enter that list and
list name after all they are the same.
Thanks
Vincent Davis
On Wed, Feb 4, 2009 at 10:18 AM, Vincent Davis <vinc...@vincentdavis.net>wrote:
> I know nothing but that sucks. I can think of a lot of times I would like
> to do something similar. There really is no way to do this, it seems like
> there would be some simple way kind of like str(listname) but backwards or
> different.
> Thanks
> Vincent Davis
>
>
>
>
> On Wed, Feb 4, 2009 at 10:07 AM, MRAB <goo...@mrabarnett.plus.com> wrote:
>
>> Vincent Davis wrote:
>> > Sorry for not being clear I would have something like this x = [1, 2,
>> > 3,5 ,6 ,9,234]
>> >
>> > Then def savedata(dataname): ..........
>> >
>> > savedata(x)
>> >
>> > this would save a to a file called x.csv This is my problem, getting
>> > the name to be x.csv which is the same as the name of the list.
>> >
>> > and the data in the file would be 1,2,3,5,6,9,234 this parts works
>> >
>> The list itself doesn't have a name. You need to pass in both the name
>> and the list:
>>
>> def savedata(name, data): ..........
>>
>> savedata("x", x)
>>
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>>
>
>
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