Hendrik van Rooyen <mail <at> microcorp.co.za> writes: > > One can go from lb = ['b','a','n','a','n','a'] > to s = "banana" by using s = "".join(lb) > > Is there a way to go the reverse route?
| >>> list('Hendrik') ['H', 'e', 'n', 'd', 'r', 'i', 'k'] Bonus extras: try tuple() and set() > I have not been able to find one. > > It is obviously easy to write a for char in s loop > or list comprehension, Aha! try a functional equivalent of a list comp: | >>> map(None, 'Hendrik') ['H', 'e', 'n', 'd', 'r', 'i', 'k'] > using lb = s.split("") would have been nice > as a complement to s = "".join(lb). object_of_type_X(something) is nicer IMHO. > Split is already full of magic, it could do with more. Both str.split and re.split are /too/ full of magic IMHO. -- http://mail.python.org/mailman/listinfo/python-list