Paul Rubin <no.email@nospam.invalid> writes:
>   FORALL P. [ P(0) and P(n) -> P(n+1) ]

Sorry, that was supposed to say

  FORALL P. [ (P(0) and P(n) -> P(n+1)) -> forall n. P(n) ]

FORALL quantifies over formulas and forall quantifies over numbers.

Maybe something is still missing from the above ;-).
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