Let me know if I am completely going the wrong way on this... import maya.OpenMaya as om import maya.cmds as cmds
cam = cmds.camera(p=(-10,10,5))[0] loc = cmds.spaceLocator()[0] cmds.move(6, 2, -8, loc) cmds.select(cam, loc, r=True) dag = om.MDagPath() sel = om.MSelectionList() om.MGlobal.getActiveSelectionList(sel) sel.getDagPath(0, dag) camFn = om.MFnCamera(dag) sel.getDagPath(1, dag) tranFn = om.MFnTransform(dag) p = camFn.eyePoint(om.MSpace.kWorld) print p.x, p.y, p.z p2 = tranFn.getTranslation(om.MSpace.kWorld) print p2.x, p2.y, p2.z print "Distance:", p.distanceTo(om.MPoint(p2)) print "Depth:", abs(p2.z - p.z) # Distance: 22.1133443875 # Depth: 13.0 Wouldn't the depth just be the difference in z values between your world points? On Mon, Aug 27, 2012 at 9:01 AM, vux <[email protected]> wrote: > distance --> is (cameraCenter-objectCenter).distance() > but i need length of perpendicular-projected point to cameraPlane >>> >>> > -- > view archives: http://groups.google.com/group/python_inside_maya > change your subscription settings: > http://groups.google.com/group/python_inside_maya/subscribe -- view archives: http://groups.google.com/group/python_inside_maya change your subscription settings: http://groups.google.com/group/python_inside_maya/subscribe
