On 22 Jan 2001, at 22:44, Christopher Cave wrote:
> 130 lc z(,0),z(,1),u
Um, just what exactly are you trying to do here?
by z(,1), do you mean that you want to pass all of z(x,1) (ie. z(0,1)
and z(1,1)), or all of z(1,x) (i.e. z(1,0) to z(1,3)?
Anyway, there is something wrong: try printing y(0) and y(1) in the
lc routine.
You'll see that y(1)=0, and not 20 or 80, despite this being printed
when you print all of y!
Actually, y(1) correspond to z(0,2) - (try it out, fill it with any value).
I'm not sure why yet.
Wolfgang
