> exp(log(1:11)) [1] 1 2 3 4 5 6 7 8 9 10 11 > 2^log(1:11, 2) [1] 1 2 3 4 5 6 7 8 9 10 11 > 2^logb(1:11, 2) [1] 1 2 3 4 5 6 7 8 9 10 11 > 10^log10(1:11) [1] 1 2 3 4 5 6 7 8 9 10 11 > 2^log2(1:11) [1] 1 2 3 4 5 6 7 8 9 10 11
Does this answer the question?
hope this helps. spencer graves
Heather J. Branton wrote:
Dear R-users,
I have a basic question about how to determine the antilog of a variable.
Say I have some number, x, which is a factor of 2 such that x = 2^y. I want to figure out what y is, i.e. I am looking for the antilog base 2 of x.
I have found log2 in the Reference Manual. But I am struggling how to get the antilog of that.
Any help will be appreciated!
> version
platform i386-pc-mingw32
arch i386 os mingw32 system i386, mingw32 status major 1 minor 9.1 year 2004 month 06 day 21 language R
...heather
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