Alan Watson wrote: > Furthermore, suppose I have a Scheme with that uses both IEEE > single-precision and IEEE double-precision formats for real numbers. > Suppose I write x|24. If x is a normalized number, the implementation > "should" represent it using a single-precision format. If x is a > denormalized number, the representation "should" represent it using a > double-precision format (because denormalized single-precision numbers > have fewer than 24 bits of precision).
And, better yet, in a Scheme has double and extended precision formats, if I write "x" (without an explicit precision and with an e exponent) and if x is a denormalized double-precision value, then the implementation "should" use an extended-precision format. Regards, Alan _______________________________________________ r6rs-discuss mailing list [email protected] http://lists.r6rs.org/cgi-bin/mailman/listinfo/r6rs-discuss
