`syntax?` is #t no matter what. `syntax-source-module` is close, but according to the docs, it can still be #f even if the syntax object has a lexical context.
I considered this: (define (no-lexical-context? stx) (equal? stx (strip-context stx))) But `equal?` doesn't work here. (Side question: does `equal?` ever return #t for syntax objects, other than the trivial case of `(equal? stx stx)`?) -- You received this message because you are subscribed to the Google Groups "Racket Developers" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-dev+unsubscr...@googlegroups.com. To post to this group, send email to racket-dev@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/racket-dev/f1f6b0c5-4658-40d0-8b18-1fbc4a63eb08%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
