I thought it was possible to destructure a list in for, but I've been searching/experimenting for a while without success. I noticed this example in the docs:
(for ([(i j) #hash(("a" . 1) ("b" . 20))]) (display (list i j))) So, I assumed I could do this: (for ([(i j) '(("a" 1) ("b" 20))]) (display (list i j))) But that doesn't work. I'm trying to avoid something as verbose as: (for ([(pair) '(("a" 1) ("b" 20))]) (match-let ([(list i j) pair]) (display (list i j)))) Why do elements of a Hash provide 2 values to for, where a 2-tuple list does not? Is there a more direct way to destructure a list in for? Thanks, Brian -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.