Hi, Karen:
OMG.....it works beautifully...... I only had to make one modification, and it
was off and running.
I appreciate it so much..
Thanks again.
Jim
On Monday, July 26, 2021, 12:11:11 PM EDT, 'Karen Tellef' via RBASE-L
<[email protected]> wrote:
Ah, that's the piece of info we all needed. So the user is NOT going to pick
the file? So then the file is going to be sitting somewhere in a directory and
you just want to pick up the file?
One way is to get a DIR of the directory into a file, load it into a table and
then use a SELECT... INTO to get the filename. Of course you would add lots
of error checking. But code like the following
Karen
OUTPUT c:\temp\file.txt
DIR d:\YourDir\*.csv
OUT SCR
DROP TABLE tmpFile
CREATE TEMP TABLE tmpFile (dirfiledate TEXT 10, dirfiletime TEXT 8, +
dirfilesize TEXT 10, dirFilename TEXT 100 )
SET NULL -0-
LOAD tmpFile FROM c:\temp\file.txt AS FORMATTED USING +
dirfiledate 1 10, dirfiletime 13 20, dirfilesize 31 40 dirfilename 42 141
SET NULL ' '
DELETE ROWSFROM tmpFile WHERE dirfilename IS NULL OR dirfilename LIKE
'byte%' +
OR dirfilename = '.' OR dirfilename = '..' OR dirfiledate CONTAINS
'directory'
-----Original Message-----
From: 'jim schmitt' via RBASE-L <[email protected]>
To: [email protected]
Sent: Mon, Jul 26, 2021 10:46 am
Subject: Re: [RBASE-L] - Capture a file Name possible
Hi, Tony ,
Thanks for the speedy reply , but there will be only one PAYMENTS....csv file
each day, and I would like to get the file name without having the operator to
choose it.
If I could get the name in a var, I could parse the date and capture the date.
Thanks,
Jim On Monday, July 26, 2021, 02:49:51 AM EDT, Tony IJntema
<[email protected]> wrote:
If the filename does not have always the same length, you can use a procedure
like this
-- capture the file name using procedure of Tony Luck
SET VAR vfile = 'PAYMENTS_637467300105556434-20210120-030011.csv'
-- (SLOCP(TextNoteVarcharValue,string,occurrence))
-- assuming '-' is always used in the filename
-- locate startposition
SET VAR V_STARTPOSITION = ( (SLOCP(.vfile ,'-',1)) + 1)
-- (SGET(text,nchar,pos))
-- get datevalue as a textvalue
SET VAR V_PAYMENTDATE_TXT TEXT = (SGET(.vfile ,8,.V_STARTPOSITION) )
-- (RDATE(mon,day,yr))
-- convert text value to a date value
SET VAR V_PAYMENTDATE DATE = (RDATE( (NINT( (SGET(.V_PAYMENTDATE_TXT,2,5))
)), (NINT( (SGET(.V_PAYMENTDATE_TXT,2,7)) )), (NINT(
(SGET(.V_PAYMENTDATE_TXT,4,1)) )) )) -- Regards Tony IJ
Op 26-07-2021 om 04:39 schreef Tony Luck:
There's a few ways to achieve that, here's one I use to capture the file name
of a file we import twice daily using a CHOOSE statement that popups up the
files for the operator. CHOOSE vfile FROM #LFILES IN &vdirfile TITLE 'Press ESC
to Exit' +
CAPTION 'Am Data Import File' OPTION LIST_FONT_SIZE 12 +
TITLE_FONT_SIZE 12 | TITLE_FONT_COLOR BLUE
From there, if the file name always places the date in the same spot you can
use SGET function to extract it.
P.S. I use an ampersand variable to store the network directory the file is
loaded to.
On Mon, Jul 26, 2021 at 12:07 PM 'jim schmitt' via RBASE-L
<[email protected]> wrote:
Hello, Group:
I have an application where the operator will be receiving a CSV 'payments'
file each day and the file has a rather long file name.
Sample file name: PAYMENTS_637467300105556434-20210120-030011.csv
Notice that the processing date (20210720) is buried inside the file name.
Is it possible within RBASE to programmatically capture the file name in a
variable so that I can interrogate the variable to obtain the processing date ?
Thanks,
Jim --
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