As a former Minnesotan, I completely understand :) No need to join anything to have fun on a bike. Keep riding!
Brian Now a Seattlite On Tue, Jan 4, 2011 at 5:47 PM, EricP <[email protected]> wrote: > Our brevet society is fairly new (2008?). And one needs to be a > member of the Twin Cities Bicycle Club ($25 a year) to join. And > yes, I usually state will not join a club that would have me as a > member. (Do believe they also highly encourage RUSA membership, > although that is not explicity stated on their page.) > > The fact I don't "fit in" with the local establishment of riders is a > secondary issue. > > Eric Platt > St. Paul, MN > > On Jan 4, 1:01 pm, Anne Paulson <[email protected]> wrote: > > On Tue, Jan 4, 2011 at 10:45 AM, Steve Palincsar <[email protected]> > wrote: > > > > > It's $10 per year to join the DC area randonneur club, and $5 per > event. > > > Considering how much effort the organizers put into setting up the > > > events, I think that's well worth it, and I'm sure it scarcely covers > > > the expenses. > > > > In my area one doesn't have to join the club putting on the event. > > That's probably because we're blessed with four different randonneur > > clubs in reasonable driving distance, so local randonneurs sample all > > the clubs' brevets. > > > > -- > > -- Anne Paulson > > > > My hovercraft is full of eels > > -- > You received this message because you are subscribed to the Google Groups > "RBW Owners Bunch" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<rbw-owners-bunch%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/rbw-owners-bunch?hl=en. > > -- You received this message because you are subscribed to the Google Groups "RBW Owners Bunch" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/rbw-owners-bunch?hl=en.
