That worked. I wanted the total number of review requests, not the number of reviews. Perhaps that could be added as a column some day to the groups page.
On Jan 5, 2:21 pm, Christian Hammond <chip...@chipx86.com> wrote: > On Tue, Jan 5, 2010 at 10:04 AM, Chris Clark <chris.cl...@ingres.com> wrote: > > grimbeaver wrote: > > >> I need a simple way to get the total number of reviews in a group. > >> We've assigned all the code reviews into groups based on project. > >> Project management has to report the total number of code reviews > >> completed for a project to our partner. When you look at the group > >> view it only gives you a count of the pending reviews, no total > >> count. Obviously in an ideal world there will be better reports some > >> day, but for now I just need an easy way to get this number when > >> needed. > > > Off the top of my head there are 2 options: > > > 1. use the Django manage shell and write simple Python queries > > 2. access the database directly, e.g. using native sql terminal > > monitor tools and query the table(s) directly > > > I don't have queries for these but it probably wouldn't take long by poking > > around. The Django tutorials are pretty good if you want to try option #1 > > which requires basic Python skills. Option #2 requires basic SQL skills. > > > If you create useful scripts they would be good to post back to the mailing > > list. > > > Chris > > Yeah, these options are necessary for now. > > Is it the total number of reviews, or review requests? > > To get into the Python shell for Review Board, run: > > $ rb-site manage /path/to/site shell > > Then: > > >>> from django.db.models import Count > >>> from reviewboard.reviews.models import ReviewRequest > >>> > >>> # Total number of public review requests to a group (pending and > closed) > >>> review_requests = ReviewRequest.objects.to_group("yourgroupname", > status=None) > >>> print review_requests.count() > >>> > >>> # Total number of public reviews to all review requests in a group > >>> print > review_requests.filter(reviews__public=True).aggregate(Count("reviews"))['r > eviews__count'] > > I think that should work off-hand. Let me know if there are problems with > it. > > Christian > > -- > Christian Hammond - chip...@chipx86.com > Review Board -http://www.reviewboard.org > VMware, Inc. -http://www.vmware.com
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