Github user squito commented on the issue:
https://github.com/apache/spark/pull/21698
yeah, you'd have to sort the entire record. I think originally it didn't
seem like that would work, because you don't know that `T` is sortable for
`RDD[T]`. But after a sort, you've got bytes, so you can at least sort the
serialized bytes of `T`. Note that you don't want to do the entire
repartitioning based on that, since you won't get a good distribution for
skewed data. But it can give you a deterministic order as an *additional*
sort, just within one partition.
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